Answer:
[tex]1)9-8=1\\2) 10(9+8)=170\\3) \frac{13+7}{2} =10\\4) \frac{9(6)+30}{6} =14\\5)2(9)+4=22[/tex]
for the next question i'm not sure but here is what i understand:
biggest size we solve it by the first equation so it will be [tex]132=\frac{2d}{3} +3 \\d=193.5\\[/tex]
and the smallest it will be by the second equation [tex]132=\frac{d}{4} -3 \\d=540[/tex]
Step-by-step explanation:
for the fist question: just instead of the a write 9 and c write 9 and so on
just remove the alphabet and put the number
