Refer to the image. Prove that the area of triangle ABE = the area of triangle BFC?

Answer:
In ΔABE and ΔACF,
∠BAE=∠CAF (Common angle)
∠AEB=∠AFC ....(∵BE⊥AC and CF⊥AB)
BE=CF (Given that altitudes are equal)
By AAS criterion of congruence,
ΔABE≅ΔACF
Hence,
AB=AC (by CPCT)
Step-by-step explanation:
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