Answer :
pH + pOH = 14
pH
= 14 - pOH
= 14 - 11
= 3
pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M
pH
= 14 - pOH
= 14 - 11
= 3
pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M