Answer:
[tex](x-6)^2=8[/tex]
Step-by-step explanation:
[tex]x^2-12x+32=4[/tex]
[tex]x^2-12x+32+4=4+4[/tex]
[tex]x^2-12x+36=8[/tex]
[tex](x-6)^2=8[/tex]
Basically, you need to add a number to both sides so that you can reduce the left side to a square. In this case, you add 4.
