I shall give the right answer brainliest

Answer:
A. [tex]-\frac{1}{9}[/tex]
Step-by-step explanation:
-([tex]3^-^5[/tex])([tex]3^3[/tex]) = [tex]-\frac{1}{9}[/tex]
please let me know if I am wrong.
hope this helped.
Answer:
A
Step-by-step explanation:
[tex]-\left(3^{-5}\right)\left(3^3\right)[/tex]
[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}[/tex]
[tex]3^{-5}\cdot \:3^3=3^{-5+3}[/tex]
= [tex]-3^{-5}\cdot \:3^3[/tex]
[tex]\mathrm{Add/Subtract\:the\:numbers:}\:-5+3=-2[/tex]
[tex]=-3^{-2}[/tex]
= [tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}[/tex]
[tex]3^{-2}=\frac{1}{3^2}[/tex]
= [tex]=-\frac{1}{3^2}[/tex]
[tex]3^2=9[/tex]
= [tex]=-\frac{1}{9}[/tex]