The chemical equation below shows the combustion of methane (ch4). Ch4 + 2o2 right arrow. Co2 + 2h2o the molar mass of oxygen gas (o2) is 32. 00 g/mol. The molar mass of carbon dioxide (co2) is 44. 01 g/mol. What mass of co2, in grams, will form when 8. 94 g o2 completely react?.

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole
O₂: 2 moles
CO₂: 1 mole
H₂O: 2 moles

The molar mass of the compounds is:

CH₄: 16.04 g/mole
O₂: 32 g/mole
CO₂: 44.01 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CH₄: 1 mole× 16.04 g/mole= 16.04 grams
O₂: 2 moles× 32 g/mole= 64 grams
CO₂: 1 mole× 44.01 g/mole= 44.01 grams
H₂O: 2 moles× 18 g/mole= 36 grams

Then the following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44.01 grams of CO₂, 8.94 grams of O₂ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{8.94 grams of O_{2} x44.01 grams of CO_{2} }{64 grams of O_{2}}[/tex]

mass of CO₂= 6.15 grams

Finally, 6.15 grams of CO₂ are formed when 8.94 grams of O₂ reacts completely.

Learn more about reaction stoichiometry:

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