i just forgot this like ;-;

Answer:
[tex] \boxed{\bf \dfrac{64}{729} }[/tex]
Hence,
[tex]\boxed{\bf \: \bigg( \dfrac{2}{3} \bigg) {}^ {6} = \dfrac{64}{729}} [/tex]
Step-by-step explanation:
Given arithmetic expression is :-
[tex]\sf \longmapsto(2/3) {}^{6} [/tex]
This expression may be rewritten as :-
[tex]\sf \longmapsto \bigg(\dfrac{2}{3} \bigg) {}^{6} [/tex]
6 is the index and 2/3 is the base.
In words, this may be represented as 2/3 raised to the Power 6.
Let's calculate.
It means that 2 is raised to the power of 6 and 3 is also raised to the power 6.
That is,
[tex]\sf \longmapsto \dfrac{ {2}^{6} }{ { 3}^{6} } [/tex]
It will be represented as,
[tex]\sf \longmapsto \: \dfrac{2 \times 2 \times 2 \times 2 \times 2 \times 2}{3 \times 3 \times 3 \times 3 \times 3 \times 3} [/tex]
On Simplification:-
[tex]\sf \longmapsto \dfrac{64}{729} [/tex]
In Decimal:-
[tex]\sf \longmapsto0.08(approx .)[/tex]
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I hope this helps!
Please let me know if you have any questions.
~MisterBrian