[tex]\text{Given that,}\\\\\text{Density of iron, }~ \rho = 7 ~\text{g cm}^{-3} = 7 \times 10^{3}~ \text{kg m}^{-3}\\\\\\\text{Mass, m =14 g =} ~ 14 \times 10^{-3} ~\text{kg}\\\\\\\text{Volume of iron,}~ V = \dfrac{m}{\rho} = \dfrac{14 \times 10^{-3}}{7\times 10^{3}} = 2 \times 10^{-6} ~~ m^3[/tex]
