Answer :
Answer:
[tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = 9 ,\ x \neq 0[/tex]
General Formulas and Concepts:
Pre-Algebra
Evaluations
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Algebra I
Distributive Property
Terms/Coefficients
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle \frac{4(3x)^2}{(2x)^2}[/tex]
Step 2: Simplify:
- Rewrite [Exponential Distributive Property]: [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{4(3^2x^2)}{2^2x^2}[/tex]
- [Order of Operations] Evaluate exponents: [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{4(9x^2)}{4x^2}[/tex]
- [Order of Operations] Multiply: [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{36x^2}{4x^2}[/tex]
- Simplify: [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = \frac{36}{4} ,\ x \neq 0[/tex]
- [Order of Operations] Divide: [tex]\displaystyle \frac{4(3x)^2}{(2x)^2} = 9 ,\ x \neq 0[/tex]
[tex]\\ \sf\longmapsto \dfrac{4(3x)^2}{(2x)^2}[/tex]
[tex]\\ \sf\longmapsto\dfrac{ 4(9x^2)}{4x^2}[/tex]
[tex]\\ \sf\longmapsto \dfrac{36x^2}{4x^2}[/tex]
- Take x^2 common and cancel.
[tex]\\ \sf\longmapsto \dfrac{x^2}{x^2}\left(\dfrac{36}{4}\right)[/tex]
[tex]\\ \sf\longmapsto \dfrac{36}{4}[/tex]
[tex]\\ \sf\longmapsto 9[/tex]