Answer:
Answer below
Step-by-step explanation:
Time can not be negative from any perspective. Hence, the correct answer is 10.16 seconds.
The equation of the path of a rocket is given that is y= x^2 + 153x + 98
We need to determine the time that the rocket will hit the ground.
Now, if the rocket hits the ground after the launching then the overall displacement at the time of hitting the ground will be zero.
Therefore, the value of y is 0.
Thus, -16x^2 +153x + 98 = 0
Now, the formula for finding the roots of the quadratic equation
ax^2 +bx +c = 0 is given as:
[tex]x^{1} =\frac{-b+\sqrt{b^2 -4ac} }{2a}[/tex]
[tex]x^2 = \frac{-b -\sqrt{b^2 -4ac} }{2a}[/tex]
Comparing the expression with the standard form of the equation.
a = -16b = 153 and c = 98
By applying the formula there are two values are come that is,
x^1 = -0.602555
x^2 = 10.1651
Time can not be negative from any perspective.
Hence, the correct answer is 10.16 seconds.
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(Hope this helps can I pls have brainlist (crown)☺️)
