someone please help me

Given info:- In ∆ABC, right-angled at c in which AB = 10in, BC = 26 in and we have to find out the measure of AC = ?
Explanation:
In right angled ∆OCB, AC ⟂ CB,
AB² = AC²+CB²
[By Pythagoras theorem]
(10)² = AC²+(26)²
10*10 = AC²+(26*26)
100 = AC²+676
AC² = 676-100
AC² = 576
AC = √(576)
AC = 24 in.
Hence, the measure of right-agled in which AC is 24 in.
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