Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.

I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]

But I don't understand what steps I have to take to solve that equation


Answer :

From Newton's law of gravity, the force of gravity is 245 Newtons

To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters

Mass m = 25 kg

Mass of the earth M = 5.97x10^24kg

Radius r = 6.38x10^6m

Force F = ?

The formula to calculate the force of gravity is

F = (GMm)/[tex]r^{2}[/tex]

Where G = 6.67 x [tex]10^{-11}[/tex]

Substitute all the parameters

F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2

F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]

F = 244.56 N

F = 245 Newtons (approximately)

Therefore, the force of gravity is 245 Newtons

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