My question is in the attachment.

Answer:
5 and 25
Step-by-step explanation:
let the son's age be x then the father's age is x + 20
In 5 years
son = x + 5 and father = x + 20 + 5 = x + 25
Then
x + 25 = 3(x + 5) ← father is three times as old as son
x + 25 = 3x + 15 ( subtract x from both sides )
25 = 2x + 15 ( subtract 15 from both sides )
10 = 2x ( divide both sides by 2 )
5 = x and x + 20 = 5 + 20 = 25
si=on is 5 and father is 25
Answer:
The son is 5 and the father is 25.
Step-by-step explanation:
We can do this using Algebra.
Let the son be x years old.
Then the father's age is x + 20 years.
After 5 years the father's age is x + 25 and the son is x + 5 years.
So we can write the equation:
x + 25 = 3(x + 5)
x + 25 = 3x + 15
25 - 15 = 3x - x
10 = 2x
x = 5.
So the father's present age is 20 + 5 = 25 and the son is 5 years old.