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A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of the stone if it hit the plane a distance L down the slope from the point of launch?

Answer :

Answer:

S = V t     where S is the horizontal distance traveled

1/2 g t^2 = H       where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

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