Answer:
t[1] = 120; t[n] = t[n-1]/n, n ≥ 2
Step-by-step explanation:
The first two terms have a ratio of 1/2. The next two terms have a ratio of 1/3. The terms after that have a ratio of 1/4. It seems that the divisor increases as n increases. In fact, the n-th term is the previous one divided by n.
The first term is 120, so ...
t[1] = 120
Using the above-described rule, ...
t[n] = t[n-1]/n . . . . for n ≥ 2
