The three consecutive terms in an AP are (k+1) ,3k and (4k+2)
We know that
If a,b,c are the three consecutive terms in an AP then b = (a+c)/2
now ,
Let a = k+1 , b = 3k and c = 4k+2
⇛3k = (k+1+4k+2)/2
⇛3k = (5k+3)/2
⇛2×3k = 5k+3
⇛6k = 5k+3
⇛ 6k-5k = 3
⇛ k = 3
The value of k = 3
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