Answered

A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an acceleration of 2.00 m/s^2 downwards?

Answer :

LANUELGO

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

Given the following data:

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 [tex]m/s^2[/tex]

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

[tex]Total \;mass=2 + 97[/tex]

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Force = mass \times acceleration[/tex]

Substituting the given parameters into the formula, we have;

[tex]Force = 99 \times 2[/tex]

Net force = 198 Newton

Read more here: https://brainly.com/question/24029674

Go Question: Other Questions