Answer :
The no. of miles driven for the cost of using Taxi A to be $2 greater than the cost of using Taxi B is; 10 miles.
For taxi A;
- C(a) = 5 + 1.25m
For taxi B;
- C(b) = 8 + 0.75m
According to the question;
- For a certain drive, the cost of using Taxi A is $2 greater than the cost of using Taxi B.
I.e; When m = m; C(a) = C(b) + 2.
Therefore;
- C(b) +2 = 5 + 1.25m...........eqn(1)
- C(b) = 8 + 0.75m......eqn(2)
The no of miles driven can then be evaluated by solving the equation simultaneously;
Substraction of eqn(2) from (1) ; we have;
- 2 = -3 + 0.5m
- 5 = 0.5m
- m = 5/0.5
- m = 10 miles.
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