Answered

100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

Answer :

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

[tex]\frac{M1V1}{V2} = M2[/tex]

[tex]\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M[/tex]

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