The volume of the bin is the amount of books it can contain.
455 books will fit in the bin
The dimension of the book is given as:
[tex]\mathbf{Book = 0.75ft, 0.75ft, 0.25ft}[/tex]
The dimension of the bin is given as:
[tex]\mathbf{Bin = 4ft, 4ft, 4ft}[/tex]
Start by calculating the volume of the book
[tex]\mathbf{Book = 0.75ft \times 0.75ft\times 0.25ft}[/tex]
[tex]\mathbf{Book = 0.140625ft^3}[/tex]
Next, calculate the volume of the bin
[tex]\mathbf{Bin = 4ft \times 4ft \times 4ft}[/tex]
[tex]\mathbf{Bin = 64ft^3}[/tex]
So, the number of books (n) is:
[tex]\mathbf{n = \frac{Bin}{Book}}[/tex]
This gives
[tex]\mathbf{n = \frac{64ft^3}{0.140625ft^3}}[/tex]
Cancel out the units
[tex]\mathbf{n = \frac{64}{0.140625}}[/tex]
[tex]\mathbf{n = 455.11}[/tex]
Remove the decimals
[tex]\mathbf{n = 455}[/tex]
Hence, 455 books will fit in the bin
Read more about volumes at:
https://brainly.com/question/15861918
