if 3x/4 - 13 = -9 then what is the value of x^2

Answer:
x² = [tex]\frac{256}{9}[/tex]
Step-by-step explanation:
[tex]\frac{3x}{4}[/tex] - 13 = - 9 ( add 13 to both sides )
[tex]\frac{3x}{4}[/tex] = 4 ( multiply both sides by 4 to clear the fraction )
3x = 16 ( divide both sides by 3 )
x = [tex]\frac{16}{3}[/tex]
Then
x² = ( [tex]\frac{16}{3}[/tex] )² = [tex]\frac{16^2}{3^2}[/tex] = [tex]\frac{256}{9}[/tex]