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Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
other, Porsha pushes off Zorn with a force of 168 N. Assume the friction between the skaters and the ice is
negligible.

Answer :

NUHULAWAL20GO

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

  • Mass of Porsha; [tex]m_{porsha} = 60kg[/tex]
  • Mass of Zorn; [tex]m_{zorn} = 40kg[/tex]
  • Force of Porsha push; [tex]F_{porsha} = 168N[/tex]

Magnitude of Porsha's acceleration; [tex]a = \ ?[/tex]

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

[tex]F = m*a[/tex]

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

[tex]168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2[/tex]

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

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