Answer:
[tex]1\dfrac{11}{16}[/tex]
Step-by-step explanation:
[tex]\left(2 + \dfrac{2}{3}\right)^{2} =\left(\dfrac{2*3}{1*3}+\dfrac{2}{3} \right)^{2}\\\\\\=\left( \dfrac{6}{3}+\dfrac{2}{3} \right)^{2}\\\\\\=\left( \dfrac{8}{3} \right)^{2}\\\\=\dfrac{64}{9}[/tex]
12 ÷ (2 + 2/3)² = 12 ÷ (64/9)
[tex]= 12 *\dfrac{9}{64}\\\\= 3 *\dfrac{9}{16}\\\\= \dfrac{27}{16}\\\\\\= 1\dfrac{11}{16}[/tex]
