Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 1.22

Answer :

Malus's law allows us to find the result for which is the angle of the polarizer for a reduction of the intensity is:

          θ = 34.9º

Malus's law establishes a mathematical relationship for the light transmitted by a polarizer is:

          I = I₀ cos² θ

where I and I₀ are the transmitted and incident intensities, respectively, θ is the angle between the two polarizers.

They indicate that the incident light is polarized, so we do not need the first polarized to create the polarized light, ask what the polarized angle should be for the intensity to be reduced by a factor.

           [tex]\frac{I_o}{I } = 1.22 \\\frac{I}{Io} = 0.81967[/tex]

           

Let's use Malus's law

          i / Io = cos² θ

           

          cos θ = [tex]\sqrt{\frac{I}{I_o} }[/tex]  

          θ = cos⁻¹1 0.81967

          θ = 34.9º

In conclusion, using Malus's law we can find the angle of the polarized for a reduction of the intensity is:

          θ = 34.9º

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