Answer:
Step-by-step explanation:
1) x +y = 3
Subtract 'x' from both sides
y = -x + 3
2) x - 3y = 12
Subtract 'x' form both sides.
-3y = -x + 12
Divide the entire equation by (-3)
[tex]\dfrac{-3y}{-3}=\dfrac{-x}{-3}+\dfrac{12}{-3}\\\\\\y = \dfrac{1}{3}x-4[/tex]
3) 5x + 2y = 10
Subtract 5x from both sides
2y = -5x + 10
Divide the entire equation by 2
[tex]\dfrac{2y}{2}=\dfrac{-5x}{2}+\dfrac{10}{2}\\\\\\y = \dfrac{-5}{2}x + 5[/tex]
4) y = 6x + (1/3)
It is already in y =mx +b form
5)
[tex]y=\dfrac{1}{x}*x-15\\\\\\y = 1-15\\\\y = -14\\\\y=0x -14[/tex]
