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A sample of an unknown gas occupies 5.51 L at 1.31 atm. What pressure would thisgas exert in a 0.520 L container if the temperature is held constant?

Answer :

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Answer:

13.9atm

Explanation:

Use Boyle's Law: P1V1 = P2V2

Manipulate the equation: P2 = P1V1/V2

Substitute the values: P2 = (1.31atm)(5.51L)/0.520L

P2 = 13.88096atm

Optionally round to 3 sig figs to get 13.9atm

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