The fuel released 90 calories of heat.
Let suppose that water experiments an entirely sensible heating. Hence, the heat released by the fuel is equal to the heat absorbed by the water because of principle of energy conservation. The heat released by the fuel is expressed by the following formula:
[tex]Q = m\cdot c \cdot \Delta T[/tex] (1)
Where:
If we know that [tex]m = 10\,g[/tex], [tex]c = 1\,\frac{cal}{g\cdot ^{\circ}C}[/tex] and [tex]\Delta T = 9\,^{\circ}C[/tex], then the heat released by the fuel is:
[tex]Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)[/tex]
The fuel released 90 calories of heat.
We kindly invite to check this question on sensible heat: https://brainly.com/question/11325154
