A sample of a compound is decomposed in the laboratory and produces 72.1 g carbon, 12.1 g hydrogen, and 48.0 g oxygen. Calculate the empirical formula of the compound.

Answer :

Answer:

empirical formula is C6H12O3

Explanation:

A sample of a compound is decomposed in the laboratory and produces

72.1 g carbon, 12.1 g hydrogen, and 48.0 g oxygen. Calculate the empirical formula of the compound.

divide the gm by the atomic mass and ratio the results

C=72.1/12.01 =6.00

H = 12.1/1.01 = 11,98 =~12

O =48.0/16 = 3

empirical formula is C6H12O3