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A train with a total mass of 2.1 × 106kg rises578 m while traveling a distance of 54 km atan average speed of 11 km/h. The frictionalforce is 0.8 percent of the weight.Find the kinetic energy of the train. Theacceleration of gravity is 9.81 m/s2.Answer in units of MJ.

Answer :

ONYEBUCHINNAJIGO

The kinetic energy of the train is for the given mass and speed is 9.832 MJ.

The given parameters;

  • mass of the train, m = 2.1 x 10⁶ kg
  • height, h = 578 m
  • distance traveled, s = 54 km
  • average speed, v = 11 km/h = 3.06 m/s

The kinetic energy of the train is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is the mass of the train
  • v is the speed of the train

The kinetic energy is calculated as;

[tex]K.E = \frac{1}{2} \times (2.1\times 10^6) \times 3.06^2\\\\K.E = 9.832 \times 10^6 J\\\\K.E = 9.832 \ MJ[/tex]

Thus, the kinetic energy of the train is for the given mass and speed is 9.832 MJ.

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