Answer:
[tex]219456[/tex]
Step-by-step explanation:
It must end in [tex]0,2,4,6,8[/tex] (divisible by 2 rule) and the digits must sum to a multiple of 9(divisible by 9 rule).
The digit sum is [tex]2+A+9+4+5+B=20+A+B[/tex].
We want to make [tex]A[/tex] as low as possible because it's a higher digit than [tex]B[/tex].
If [tex]A[/tex] is as low as possible, we have that the sum is [tex]20+0+7=27[/tex]. Uh-oh. [tex]B[/tex] has to be even! So [tex]A=0[/tex] doesn't work.
If [tex]A=1[/tex], we have that the sum is [tex]20+1+6=27[/tex]. Yay!
So, the answer is [tex]\boxed{219456}[/tex]
