Anybody good in math ?

Answer:
[tex]y=-0.3(x-2)^2+2[/tex]
Step-by-step explanation:
We know that the parabola faces downard, and hence must have a negative first term, so that eliminates the first and third options.
The vertex of the parabola has an x-value of 2, so it must be of the form [tex]a(x-3)^2+c[/tex].
Combining these, we have that the answer is [tex]\boxed{y=-0.3(x-2)^2+2}[/tex]