The given point to us is (3,-1) and the slope of the line is 2 . We can use the point slope form of the line as ,
[tex]\sf\longrightarrow m ( x - x_1) = y - y_1[/tex]
Substitute the values ,
[tex]\sf\longrightarrow 2( x - 3 ) = y - (-1) [/tex]
Simplify LHS and RHS ,
[tex]\sf\longrightarrow 2x - 6 = y +1 [/tex]
Put all terms on one side ,
[tex]\sf\longrightarrow \boxed{\bf 2x - y -7=0} [/tex]
