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The Leibnitz notation for the chain rule is
(1 point) Suppose y = sin(x2 - 4x). We can write y = sin(u), where u =
dy dy du
dy
du
The factors are
(written as a function of u ) and
dx du dx
du
dx
x for u to get
Now substitue in the function of
=
dy
dx
(written as a function of x ).

The Leibnitz Notation For The Chain Rule Is 1 Point Suppose Y Sinx2 4x We Can Write Y Sinu Where U Dy Dy Du Dy Du The Factors Are Written As A Function Of U And class=

Answer :

LAMMETTHASHGO

For this derivative, you could set

[tex]\boxed{u = x^2 - 4x}[/tex]

Then

[tex]y = \sin(x^2-4x) = \sin(u)[/tex]

so that

[tex]\boxed{\dfrac{\mathrm dy}{\mathrm du} = \cos(u)}[/tex]

and

[tex]\boxed{\dfrac{\mathrm du}{\mathrm dx} = 2x - 4}[/tex]

Then the chain rule gives

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \cos(u)(2x-4) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = (2x-4)\cos(x^2-4x)}[/tex]

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