Step-by-step explanation:
let the three consecutive odd number be x + 1 , x + 3 , x + 5
a/q
5 times the middle number = 5(x + 3) is
3 more than twice the sum of 1st and 3rd number = 3 + 2(x+1 + x + 5 )
so,
= 5 ( x + 3 ) = 3 + 2 ( x + 1 + x + 5 )
= 5x + 15 = 3 + 4x + 12
= 5x + 15 = 4x + 15
= -4x + 5x = 15 - 15 = 0
= x = 0
so, the 3 consecutive odd numbers are,
x + 1 = 1
x + 3 = 3
x + 5 = 5
and also a/q
5 times the middle number = 5×3 = 15
is equal to 3 more than twice the sum of 1st and 3rd number = 3 + 2(1+5) = 12 + 3 = 15
LHS = RHS
hope this answer helps you dear...take care and may u have a great day ahead!
