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Mathematics

Answered

A father was three times as old as his son fifteen years ago and four times as old as his son nineteen years ago. When was the father twice as old as the son?

Please show the working clearly!

Answer :

FULCRUMAHSOKAGO FULCRUMAHSOKAGO

Answer:

The father was twice as old as his son when he (the father) was 62 years old.

Step-by-step explanation:

(Assuming s = current age:)

f = 3(s-15)

f = 4(s-19)

3s-45 = 4s-76

31 = s

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