if the breadth of rectangle in one fourth of its length and perimeter is 60 cm ,find the length and breadth of rectangle​

Answer :

Answer:

Breadth/width = 1.936cm, length = 7.746cm

Step-by-step explanation:

Perimeter of a rectangle would be [tex]2L*2W=60cm[/tex] in this case. Breadth is width.

But we can rewrite this equation given that the width is 1/4 the length. This means 4 of the widths would equal one length.

[tex]W=\frac{1}{4}L[/tex]

[tex]L=4W[/tex]

We can substitute L with the 4W

[tex]2(4W)*2(W)=60cm[/tex]

Now we can just solve for the width W.

[tex]8W*2W=60\\16W^2=60\\W^2=\frac{15}{4} \\W=\sqrt{\frac{15}{4} } \\W=\frac{\sqrt{15} }{2}=1.936cm[/tex]

We now know the width is about 1.936cm

We can find the length given our formula before of [tex]L=4W[/tex]

[tex]L=4(\sqrt{\frac{15}{2} } )=2\sqrt{15} =7.746cm[/tex]

So the breadth/width is 1.936cm and the length is 7.746cm.

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