Answer:
1) [tex]y-6=-\frac{2}{3} (x-1)[/tex] and 2) [tex]y=-\frac{2}{3} x+\frac{20}{3}[/tex]
Step-by-step explanation:
Ikr the bots are annoying.
Point-slope form is written as: [tex]y-y_1=m(x-x_1)[/tex]
Slope intercept form is written as: [tex]y=mx+b[/tex]
We also need to find the slope before putting it in this form, which can be done by [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
1) Points given are (1,6) and (-2,8)
Slope: [tex]m=\frac{8-6}{-2-1} =-\frac{2}{3}[/tex]
You can choose either of the two points to put into the formula. I just chose (1,6)
Answer: [tex]y-6=-\frac{2}{3} (x-1)[/tex]
2) Same points as before and we have the same slope as before. All we need is to find the y intercept which is our b in the equation. You can easily do this by plugging in a point and solving for b. I will choose point (1,6) again.
[tex]6=-\frac{2}{3} (1)+b[/tex]
[tex]6=-\frac{2}{3} +b[/tex]
[tex]6+\frac{2}{3}=-\frac{2}{3} +\frac{2}{3} +b[/tex]
[tex]b=6+\frac{2}{3}=\frac{20}{3}[/tex]
Answer: [tex]y=-\frac{2}{3} x+\frac{20}{3}[/tex]
