Answer:
50.2in or 4.2ft
Step-by-step explanation:
This is a problem about proportions so I generally set up my problems like below. I just set some variable here to make it easier to refer back to the measurements for each. You don't have to do this, I am just showing it for clarity. I will convert everything to inches too. We need to find the real window height.
Mb = model building = 18in
Mw= model window = [tex]\frac{1}{9}[/tex]in
Rb = real building = 678ft = 8136in
Rw = real window = ?
[tex]\frac{Mw}{Mb}[/tex] = [tex]\frac{Rw}{Rb}[/tex]
[tex]\frac{1/9}{18}[/tex] = [tex]\frac{Rw}{8136}[/tex]
[tex]\frac{1}{9*18}[/tex] = [tex]\frac{Rw}{8136}[/tex]
[tex]\frac{1}{162}[/tex] = [tex]\frac{Rw}{8136}[/tex]
[tex]\frac{1*8136}{162}[/tex]= [tex]\frac{8136*Rw}{8136}[/tex]
[tex]\frac{8136}{162}[/tex] = Rw
[tex]\frac{452}{9}[/tex] = Rw
Rw ≈ 50.2in ≈ 4.2ft
