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A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force acting on the bicyclist?

Answer :

LANUELGO

The net force acting on the bicyclist is 11.022 Newton.

Given the following data:

  • Mass of bicyclist = 66 kg
  • Initial velocity = 0.50 m/s
  • Initial velocity = 1.50 m/s
  • Distance traveled = 6.0 meters

To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Force = mass[/tex] × [tex]acceleration[/tex]

First of all, we would determine the acceleration by using the third equation of motion;

[tex]V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}[/tex]

Acceleration, a = 0.167 [tex]m/s^2[/tex]

Now, we can find the net force acting on the bicyclist:

[tex]Force = 66[/tex] × [tex]0.167[/tex]

Force = 11.022 Newton

Therefore, the net force acting on the bicyclist is 11.022 Newton.

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