Shelly was 1km from her camp. Since her initial direction is in the North-West direction, hence the quadrant bearing will be at the 3rd quadrant
If Shelly walks 2 kilometers N30°W from her camp and then walks 2 kilometers directly east, then the distance of Shelly from the starting point can be gotten using the trigonometry identity as shown:
Let x be the required distance, hence;
[tex]x = 2 sin \theta\\x = 2sin 30^0\\x = 2(0.5)\\x=1km[/tex]
Hence Shelly was 1km from her camp. Since her initial direction is in the North-West direction, hence the quadrant bearing will be at the 3rd quadrant
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