We have that Precipitate will be form because
ksp>Ionic Product
[tex]8.7 x 10^{-14} > 6.25 * 10^{-8}[/tex]
From the question we are told
for the following equilibrium, where mgf_2 is the only species in liquid water, if the magnesium concentration is 0.0025 m and ksp=8.7×10−14, will a precipitate form?
mgf2(s)↽−−⇀mg^2 (aq) 2f−(aq)
Generally
With Solubility as mol^{-1}
[tex]s=0.0025\\\\2s=0.005[/tex]
Since from the equation RHS
[tex]mg^2 (aq) 2f−(aq)[/tex]
Therefore
Ionic Product
[tex]X=Mg^{+2} *F^-^2\\\\X=s*2s^2\\\\X=4s^3\\\\X=4*(0.0025)^3\\\\X=6.25 * 10^{-8}\\\\[/tex]
Hence
Precipitate will be form because
ksp>Ionic Product
ksp>x
8.7 x 10^{-14} > 6.25 * 10^{-8}
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