Answer:
[tex]a = \frac{49}{2}[/tex]
[tex]b = 18[/tex]
Step-by-step explanation:
Lets focus on the third equation to find a:
50 - 2a = 1
Add 2a to both sides of the equation:
50 - 2a + 2a = 1 + 2a
50 = 1 + 2a
Subtract 1 from both sides of the equation:
50 - 1 = 1 + 2a - 1
49 = 2a
Divide both sides by 2:
[tex]\frac{2a}{2} = \frac{49}{2}[/tex]
[tex]a = \frac{49}{2}[/tex]
Now substitute in the know a variable into the first equation:
[tex]2a - 3b = -5[/tex]
[tex]49 - 3b = -5[/tex]
Add 3b to both sides:
[tex]49 - 3b + 3b = -5 + 3b\\49 = -5 + 3b[/tex]
Add 5 to both sides:
[tex]49 + 5 = -5 + 3b + 5[/tex]
54 = 3b
Divide both sides by 3:
[tex]\frac{53}{3} = \frac{3b}{3}[/tex]
[tex]b = 18[/tex]
c cannot be solved as there is no c variable.
Hope this helps!
