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In the diagram below, ΔABC ∼ ΔDEF. If AC=18,BC=24. and DF=12, find EF

In The Diagram Below ΔABC ΔDEF If AC18BC24 And DF12 Find EF class=

Answer :

REINHARD10158GO

Answer:

9

Step-by-step explanation:

similar triangles.

that means there is one common factor to transform the lengths of all lines from one triangle to the other.

it looks to me DF is the longest side in DEF, and that would make it associated to BC of ABC.

so, the factor is then

BC = DF×f

24 = 12×f

=> f = 2

so, EF then is associated to AC.

AC = EF × f

18 = EF × 2

EF = 18/2 = 9

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