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what is the 8th term of the sequence whose first term is 64 and common ratio is 1/2?

Answer :

DᴀƦᴋPᴀƦᴀᴅᴏXGO

Here's the solution :

  • [tex]nth \: \: term = ar {}^{n - 1} [/tex]

here,

  • n = 8th term

  • r = 1/2

  • a = 64

now, let's find the 8th term :

  • [tex]64 \times { \bigg( \dfrac{1}{2} \bigg ) }^{8 - 1} [/tex]

  • [tex]64 \times \bigg(\dfrac{1}{2 {}^{7} } \bigg)[/tex]

  • [tex]64 \times \dfrac{1}{128} [/tex]

  • [tex] \dfrac{1}{2} \: \: \: o r \: \: \: 0.5[/tex]

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