Given m
n, find the value of x and y
m
(7x+18)
(5x-6)
(3y+11)
n

Answer:
[tex]7x + 18 + 5x - 6 = 180 \\ 12x + 12 = 180 \\ 12x = 180 - 12 = 168 \\ x = 168 \div 12 =14 \\ 3y + 11 = 7x + 18 = 7 \times 14 + 18 \\ 3y + 11 = 98 + 18 = 116 \\ 3y = 116 - 11 = 105 \\ y = 105 \div 3 = 35 [/tex]