Answered

In a sunny location, sunlight has a power density of about 1 kW/m2. Photovoltaic solar cells can convert this power into electricity with 16% efficiency.
If a typical home uses 390 kW⋅h of electricity per month, how many square meters of solar cells would be required to meet its energy requirements? Assume that electricity can be generated from the sunlight for 8 h/day.

Express your answer using two significant figures.

Answer :

OLADAYOADEMOSUGO

We require 304.69 m² of Photovoltaic solar cells to meet its energy requirements.

Since the power density of sunlight is 1 kW/m², let A be the area of the Photovoltaic solar cells. The total power from the sun is thus P = 1 kW/m² × A = A kW. Since the Photovoltaic cells are 16 % efficient, the power from the cells is 0.16 × A kW = 0.16A kW.

Also an average home uses 390 kWh. The energy used in 8 hours is thus

390 kWh/8 h = 48.75 kW.

Since this power equals the power from the photovoltaic solar cells, we have that

0.16A kW = 48.75 kW

A = 48.75 kW/0.16 kW

A = 304.69 m²

So, we require 304.69 m² of Photovoltaic solar cells to meet its energy requirements.

Learn more about Photovoltaic solar cells here:

https://brainly.com/question/16000219

Go Question: Other Questions