PLS HELP MEEE!!!! BRAINLIESTTTTT!!!!!

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Answer :

Answer:

Line: [tex]y=4/3x[/tex], Graph: desmos(.com)/calculator/tiptlly8xj

Step-by-step explanation:

First off, your slope is wrong. I will show you how to find the correct slope, and will make the graph.

The change in [tex]y[/tex] is [tex]16-8=8[/tex].

The change in [tex]x[/tex] is [tex]12-6=6[/tex].

That makes the slope [tex]8/6=4/3[/tex].

Recall point-slope form. That is, given a point [tex](x_{1}, y_{1})[/tex] and a slope [tex]m[/tex], the line through the given point with the given slope is of the form [tex]y-y_{1}=m(x-x_{1})[/tex].

Plugging in one of the points, (6, 8)(we could also use (12, 16)) to the point-slope equation gives the line: [tex]y-8=4/3(x-6)[/tex].

Converting to slope-intercept form([tex]y=mx+b[/tex])...

Simplifying the right hand side gives [tex]y-8=4/3x-8[/tex].

Adding [tex]8[/tex] to both sides gives the desired line, [tex]y=4/3x[/tex].

The graph is shown on Desmos in the answer.