Answer:
Solve by substitution;
2x +4y =8 ...(1)
[tex]2x + 4y = 8 \\ \\ 4y = 8 - 2x \\ \\ y = \frac{8 - 2x}{4} \\ \\ y = 2 - \frac{x}{2} [/tex]
We substitute y into the second equation.
2x + 2y=2 ... (2)
[tex]2x + 2y = 2 \\ \\ 2x + 2(2 - \frac{x}{2} ) = 2 \\ \\ 2x + 4 - x = 2 \\ \\ x + 4 = 2 \\ x = 2 - 4 \\ x = - 2[/tex]
And we substitute x into the equation y .
[tex]y = 2 - \frac{x}{2} \\ \\ y = 2 - \frac{( - 2)}{2} \\ \\ y = 2 + 1 \\ y = 3[/tex]
(x,y) —> (–2 , 3 )
I hope I helped you^_^
