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A penguin walks 5,00 m East to catch a fish in 30.0 sec. He catches 2 fish and decides to share with his friend. He walks back to his original position
in 28.0 sec. He then decides he is hungry again and needs another fish. He returns to his fishing spot and decides to go really fast (he is really hungry)
and gets there in 12.0 seconds

Answer :

ONYEBUCHINNAJIGO

The displacement of the penguin is 500 m East and the velocity is 41.67 m/s.

Your question is not complete, it seems to be missing the following information;

find the penguin's displacement and velocity when it returned to the fishing spot

The given parameters;

  • initial displacement forward, x₁ = 500 m
  • initial time of motion forward, t = 30 s
  • initial displacement backward, x₂ = 500 m
  • initial time of motion backward, t = 28 s
  • final displacement = 500 m
  • time of motion, for final displacement = 12 s

The displacement of the penguin when it returned to the fishing spot is calculated as;

Displacement is the change in position of an object.

Penguin's displacement = 500 m East

The velocity of the penguin is calculated as;

Velocity is the change in displacement per change in time of motion.

[tex]v = \frac{\Delta \ displacement}{time} \\\\v = \frac{500}{12} \\\\v = 41.67 \ m/s[/tex]

Thus, the displacement of the penguin is 500 m East and the velocity is 41.67 m/s.

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