Solve the attached sum (Trigonometry)

Answer: [tex]\sec \theta[/tex]
Step-by-step explanation:
The period of [tex]\sec \theta[/tex] is [tex]2\pi[/tex], so [tex]\sec(4\pi -\theta)=\sec(-\theta)[/tex]
Also, as [tex]\sec \theta[/tex] is an even function, [tex]\sec(-\theta)=\boxed{\sec \theta}[/tex]